# Fix BST with Two Nodes Swapped Given a binary search tree with two swapped nodes, the task is to…

Fix BST with Two Nodes Swapped

Given a binary search tree with two swapped nodes, the
task is to fix the binary search tree by swapping them
back.

Dry run C++ code with 2-3 complicated and long
examples.

Also calculate and explain What will be space and time
complexity and stepwise calculation of both space and time
complexity for my given C++ code .

[Explain solution C++ code of above question , step by
step and linewise explanation of code and algorithm , logic ,
how and why it works , complete and indepth description
.

I have provided c++ solution after question
.
]

C++ CODE SOLUTION

#include

struct Node
{
int key;
struct Node *left;
struct Node *right;
Node(int k){
key=k;
left=right=NULL;
}
};

void inorder(Node *root){
if(root!=NULL){
inorder(root->left);
cout<

Node *prevv=NULL,*first=NULL,*second=NULL;
void fixBST(Node* root)
{
if (root == NULL)
return;
fixBST(root->left);
if(prevv!=NULL &&
root->key

int main() {
Node *root = new Node(18);
root->left = new Node(60);
root->right = new Node(70);
root->left->left = new Node(4);
root->right->left = new Node(8);
root->right->right = new Node(80);
inorder(root);
cout<<>
fixBST(root);
int temp=first->key;
first->key=second->key;
second->key=temp;
inorder(root);
return 0;
}

Output of above code :

4 60 18 8 70 80
4 8 18 60 70 80

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