Using Kepler’s laws of planetary motion, we can derive the following expression for a circular orbit: T 2 = 4p2 a3 m where T = orbital period a = orbital radius in km = distance from the center of the earth to the orbit m = Kepler>s constant = 3.986004418 * 105 km3 /s2 The earth rotates once per sidereal day of 23 h 56 min 4.09 s.
a. Determine the orbital radius of a GEO satellite.
b. Assuming an earth radius of 6370 km, what is the orbit height h (Figure 16.1) of a GEO satellite? Note: your answer should differ slightly from the figure used in the chapter. Different sources in the literature give slightly different values.
Figure 16.1 Coverage and Elevation Angles
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