Create a menu-driven Python program that functions like a phone book. Input is from a data file…

Create a menu-driven Python program that functions like a phone book. Input is from a data file called phone.txt that consists of comma-separated values with one entry per line. The format of the input line is as follows:

name, phone

Here is my code;

class Phone_Book:
def __init__(self, contactName, number):
self.contactName = contactName
self.number = number

list=[]

def readFile(phone):
file1 = open(phone, ‘r’)
lines = file1.readlines()
countLines = 0
for line in lines:
try: x = line.split(‘,’)
# countLines += 1 list.append(Phone_Book(x[0], x[1])) # I am getting a syntax error on this line and am unaware as to why, please help!!
except ValueError: print(f’Invalid data found at line {countLines} in the file.n’)

def writeFile(phone.02):
file1 = open(phone, ‘w’)
for obj in list:
file1.write(obj.contactName + ‘,’ + obj.number)
def printEntries():
print(‘The Phone Book Details are as follows :nttNamettNumber’)
for obj in list:
print(‘{0:<20}{1:>10}’.format(obj.contactName, obj.number))

print(‘————– End of Contact List ————-nn’)

def searchPhonebook():
name=input(‘Enter name to search:’)
for obj in list:
if obj.contactName==name:
print(‘Name:’+ obj.contactName)
print(‘Phone:’+ obj.number)
def addToPhonebook():
name=input(‘Enter contact name:’)
number=input(‘Enter contact number:’)
list.append(Phone_Book(name, number))
writeFile(‘phone_book.txt’)
print(‘Contact added successfully’)

def deleteFromPhonebook():
name = input(‘Enter Contact name : ‘)
for obj in list: if obj.contactName == name:
list.remove(obj) writeFile(‘phone_book.txt’)
print(‘Contact Removed Successfully’)

def main():
phonebook=readFile(‘phone.txt’)
choices = [‘exit’, ‘search phonebook’, ‘add entry’, ‘delete entry’, ‘print phonebook’]

option = menu(choices)
while option != 0:
if option == 1:
print(‘search phonebook’)
elif option == 2:
print(‘add entry’)
elif option == 3:
print(‘delete entry’)
elif option == 4:
printEntries(phonebook)
else:
print(‘not an option’)

option = menu(choices)

I am receiving a syntax error in the second paragraph of code, as described in the line of code above.

Any ideas as to why?!

Thank you!

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