Assuming the diode to obey I = IS (eV /0.026 − 1), calculate the ratio V/I for an ideal diode with IS = 10−13 A for the applied voltages of −2, −0.5, 0.3, 0.5, 0.7, 1.0, and 1.5 V, in order to illustrate that a diode is definitely not a resistor with a constant ratio of V/I.
A semiconductor diode with IS = 10µA and a 1-k resistor in series is forward-biased with a voltage source to yield a current of 30 mA. Find the source voltage if the diode I–V equation is given by I = IS (e40V − 1). Also find the source voltage that would yield I = −8µA.
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